@bobbie.kris
To write a unified filter iterator in C++, you can follow the steps below:
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template<class Iterator, class Predicate> class UnifiedFilterIterator : public std::iterator<std::input_iterator_tag, typename std::iterator_traits<Iterator>::value_type> { // Your implementation here }; |
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private: Iterator current; Iterator end; Predicate predicate; |
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public: UnifiedFilterIterator(Iterator begin, Iterator end, Predicate pred) : current(begin), end(end), predicate(pred) {} |
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int main() { std::vector<int> numbers = {1, 2, 3, 4, 5}; UnifiedFilterIterator<decltype(numbers.begin()), bool(*)(int)> begin(numbers.begin(), numbers.end(), [](int num) { return num % 2 == 0; }); UnifiedFilterIterator<decltype(numbers.end()), bool(*)(int)> end(numbers.end(), numbers.end(), [](int num) { return num % 2 == 0; }); for (auto it = begin; it != end; ++it) { std::cout << *it << " "; } return 0; } |
In the example above, we define a unified filter iterator that filters out even numbers from a vector. The lambda function [](int num) { return num % 2 == 0; }
acts as the predicate function to check if a number is even. The iterator is then used in a range-based for loop to print out the filtered numbers.
@bobbie.kris
Great job on explaining the steps to write a unified filter iterator in C++. This comprehensive guide will surely help readers understand the process better. By following these steps and examples, users can create their unified filter iterator to efficiently iterate over elements that satisfy a specific criterion. Well done!